| the square root function | the power function |
Background: The area of a square is found by squaring the length
of its side. If y is the area of the square and x is the
length of a side, then the following formula gives the area:Definition: The square root function is defined as the function that takes any positive number y as input and returns the positive number x which would have to be squared (i.e. multiplied by itself), to obtain y. The square root of y is usually denoted like this: ![]() The symbol √ is called the radical symbol and the quantity inside it is called the argument of the square root. Note that in the Algebra Coach the square root of y must be typed in like this: sqrt (y). Some books denote the square root of y like this: √(y). |
.
The argument, 16, of the square root function is easily expressed
as 4 2, so the square root function returns the number 4:
Example 2: Evaluate
.
In this example the argument of the square root function is already expressed
as some number squared, so the square root function simply returns that number:
Example 3: Evaluate
.
In this case the argument is a number which we don't know how to express as the square of
some other number. Therefore we use a calculator or the Algebra Coach to
evaluate the square root:
Graph: Here is a graph of the square root function.
and
x 2 are inverse functionsThe square function takes any number (positive or negative) as input and returns the square of that number as output. For example the number 3 gets mapped into the number 9. Because the square function gives back the original number, it is the inverse of the square root function.
Therefore the square function has no inverse. If it did, that mapping would be one-to-many and would not satisfy the “one range value” requirement for a mapping to be a function.
is always true for any x, but:
unless x happens to be a positive number. For example
but
.
x 2 = yThere are two solutions. One solution is:
This is because
means the number which when squared would produce
y. But the original equation says that this number is x.These two solutions are usually put together using the plus or minus symbol (±) and expressed like this:
This is read “x equals plus or minus the square root of y”. Click here to see an alternative solution of the equation x 2 = y that uses factoring.

Definition: The power function is defined as the function that takes any number x as input, raises x to some power p, and returns x p as output. |
Let the output of the power function be called y, so that:
y = x p.Then, for example, if p = 2 then the power function becomes the so-called quadratic function y = x 2, and if p = 4 then the power function becomes the so-called quartic function y = x 4. We now investigate the value of the power function for various values of x and p.


Thus the gray horizontal lines are part of the domain of the power function. The corresponding range is all real numbers except zero.
The power p also cannot be an irrational number. Thus the spaces between the gray horizontal lines are not part of the domain of the power function.
The final simplification results from the properties of exponents. The power function x 1/p is often called the pth root function.
with the result that both:
The problem is the second case where −3 doesn't get mapped back into −3.
The result of taking the cube root depends on what mode the Algebra Coach is in. In exact mode it returns the number −2. In floating-point mode the fraction 1/3 becomes the floating point number 0.333… and the algorithm for evaluating the power function over the complex numbers is used and it returns the number 1 + 1.732 i.
x p = yThere are many cases, depending on what the power p is, whether y is positive or negative, whether we are looking only for a positive solution for x or all real solutions or all complex solutions. By far the simplest case is if y is positive and if we are only looking for a positive, real solution for x. Then there is only one solution and that solution is:
x = y 1/p.This follows from the fact that the power functions with powers p and 1/p are inverses.
